Solutions for May 25 Practice set

covers topics
Complex Numbers
Vectors (common to physics and mathematics)
Mole concept

1. The inequality |z-4|<|z-2| represents the region given by

a. Re(z)>0
b. Re(z)<2
c. Re(z)<0
d. none of these

Answer (d)

Answer

Let z = x+iy then

|z-4|<|z-2|

=> |z-4²|<|z-2|²
=> (x-4) ²+y²<(x-2) ²+y²
=> -8x+16<-4x+4
=>12<4x
=> x>3
Means Re(z)>3





2. The points with the position vectors 60i +3j, 40i-8j, ai-52j are collinear if

a. a = -40
b. a = 40
c. a = 20
d. none of these



If the vectors x and y are collinear,
x = py
If we take given position vectors m.n,o, it implies
o-m = p(n-m)

[(ai-52j)-( 60i +3j)] = k[(40i-8j)-( 60i +3j)]

=> (a-60)i – 55j = k(-20i-11j)
=> a-60 = -20k and -55 = -11k
=> k = 55/11
=> a = -20*5 + 60
=> a = -40


3. One molal solution is one that contains one mole of a solute in :

a. 1000 g of the solvent
b. one litre of the solvent
c. one litre of the solution
d. 22.4 litres of the solution

Answer (a)

As per the definition, molality is amount of solute per kg of solvent.

May 25 2008 Question set 1

covers topics
Complex Numbers
Vectors (common to physics and mathematics)
Mole concept

1. The inequality |z-4|<|z-2| represents the region given by

a. Re(z)>0
b. Re(z)<2
c. Re(z)<0
d. none of these


2. The points with the position vectors 60i +3j, 40i-8j, ai-52j are collinear if

a. a = -40
b. a = 40
c. a = 20
d. none of these

3. One molal solution is one that contains one mole of a solute in :

a. 1000 g of the solvent
b. one litre of the solvent
c. one litre of the solution
d. 22.4 litres of the solution


For solution see
http://iit-jee-nrao.blogspot.com/2008/05/solutions-for-may-25-practice-set.html